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f(x)/g(x)使用洛必達法則上下求導 得(1-cosx)/(anx^n-1) 繼續上下求導 sinx/(an(n-1)x^n-2) 將當x->;0,sinx~x等價無窮小,sinx換成x x/(an(n-1)x^n-2) 約去x 1/(an(n-1)x^n-3)= 1 所以n-3=0 n=3 an(n-1)=1 a=1/6
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