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任給正數ε> 0,取δ= min(ε/20,1), 則當|x-2| <δ,1 < x < 3, 囙此|x^3-8| = |x-2|*|x^2+2x+4| <ε/20*(9+6+4)<ε, 所以lim(x→2)x^3 = 8 .
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