2.設x,y為實數,且(x/1+i)*(y/1-2i)=5/1-3i,求x+y.

2.設x,y為實數,且(x/1+i)*(y/1-2i)=5/1-3i,求x+y.

:∵a/(1-i)-b/(1-2i)=5/(1-3i)左端通分得:∴(a-2ai-b+bi)/(1-2i-i+2i^2)=5/(1-3i)∴[(a-b)-(2a-b)i]/(-1-3i)=5/(1-3i)-5-15i=(a-b)-3i(a-b)-3(2a-b)-(2a-b)i根據實部等於實部,虛部等於虛部得:-5-15i=(-5a+2b)-(5…