2. Let X and y be real numbers, and (x / 1 + I) * (Y / 1-2i) = 5 / 1-3i, find x + y

: ∵ A / (1-I) - B / (1-2i) = 5 / (1-3i) the left end is divided into: ∵ (a-2ai-b + bi) / (1-2i-i + 2I ^ 2) = 5 / (1-3i) ∵ [(a-b) - (2a-b) I] / (- 1-3i) = 5 / (1-3i) - 5-15i = (a-b) - 3I (a-b) - 3 (2a-b) - (2a-b) I according to the real part equals the real part and the imaginary part equals the imaginary part: - 5-15i = (- 5A + 2b) - (5

2. Let X and y be real numbers, and (x / 1 + I) * (Y / 1-2i) = 5 / 1-3i, find x + y

2. Let X and y be real numbers, and (x / 1 + I) * (Y / 1-2i) = 5 / 1-3i, find x + y

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