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1-100的總和5050能被5整除的數從5到100共20項,其和=(5 + 100)×20/2 = 1050能被9整除的數從9到99共11項,其和=(9 + 99)×11/2 = 594既能被9又能被5整除的數從45到90共2項,其和= 45+ 90 = 135囙此,1-100以內所有…
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