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因為A的n個特徵值互异 所以A可對角化,且A相似於對角矩陣diag(a1,…,an) 又因為n階方陣B與A有相同的特徵值 所以B也可對角化,且B相似於對角矩陣diag(a1,…,an) 由相似的傳遞性知A與B相似
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