a^2-10a+b^2+6b+34=0,ab的值是?

a^2-10a+b^2+6b+34=0,ab的值是?

a^2-10a+b^2+6b+34=0
(a-5)^2+(b+3)^2=0
所以a-5=0 b+3=0
a=5 b=-3
ab=5x(-3)=-15