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你注意到這個式子有什麼特徵嗎?把帶正號的和帶負號的係數分別加一加,它們的和相等.這說明有x-1,x+1這兩個因式,於是可用待定係數法得原式=(x+1)(x-1)(2x^3+ax^2+bxx+c)拆開比較對應系數可得或者使用帶根法.令X=3,X=-2…
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