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是的,逆命題是斜邊上的中線等於斜邊一半的三角形是直角三角形. 設三角形ABC,AB邊上的中線是AD,AD=(1/2)AB,求證:C=90 證明:因為AD=BD=CD=(1/2)AB,所以A=角ACD,角B=角BAD,又A+B+C=180度,所以2(角A+B)=180度,所以A+B=90度,故C=90度.
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