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百度的參攷下用待定係數法就是要設原式=(x²;+ax+1)(x²;+bx+7)或=(x²;+ax-1)(x²;+bx-7)[因為首項可分解為x⁴;=x²;*x²;末項可分解為7=1*7或(-1)*(-7)]然後再把括號打開再合併同類項可以…
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