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設該正三棱臺上地面為ABC 下底面為A'B'C' 取BC B'C'的中點D E相連 則四邊形DEAA'為梯形 其高即為棱臺的高一條腰為側面的高 則有0.5(30*15√3)+0.5(20*10√3)=3*0.5(20+30)*x x=13√3/3 有畢氏定理得h=√(x²;-(5√3/3)²;)=4√3cm
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