1/2[x-1/2(x-1)]=3/4x-1

1/2[x-1/2(x-1)]=3/4x-1


1/2[x-1/2(x-1)]=3/4x-1
1/2(x-1/2x+1/2)=3/4x-1
1/2x-1/4x+1/4=3/4x-1
2/4x-1/4x-3/4x= -1-1/4
-1/2x= -5/4
x= -5/4*(-2)
x=5/2



(4x-1)/(x-3)=2+1/(x-3)


去分母得
4x-1=2x-6+1
2x=-4
∴x=-2
經檢驗:x=-2是方程的解



2分之x-1=3分之4x-1-1
2分之1-x =3分之4x-1 -1


兩邊乘以6得
3(1-x)=2(4x-1)-1
3-3x=8x-2-1
3+3=8x+3x
11x=6
x=6/11(11分之6)



(x-1)^3分之2x^2-4x+2


[2x^2-4x+2 ] /(x-1)^3
=2(x^2-2x+1)/(x-1)^3
=2(x-1)^2 /(x-1)^3
=2 /(x-1)