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設原來乙筐蘋果數量為X個,那甲筐蘋果數為3/4X個 從乙筐取40個後,乙筐內只有(X-40)個,甲筐內有(3/4X+40)個 此時乙筐內僅有甲筐的2/5 由此可得(X-40)= 2/5(3/4X + 40) 解得X = 80個 所以乙筐原有蘋果80個甲筐原有蘋果60個
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