函數y=3-5x-1/5x^-1(x大於0)求y最大值

函數y=3-5x-1/5x^-1(x大於0)求y最大值


y



函數y=(x+1)/(x^2+5x+6)(x>-1)的最大值
基本不等式的應用,


1/y=(x²;+5x+6)/(x+1)
=[(x+1)(x+4)+2]/(x+1)
=(x+1)(x+4)/(x+1)+2/(x+1)
=x+4+2/(x+1)
=(x+1)+2/(x+1)+3
x>-1
x+1>0
所以(x+1)+2/(x+1)>=2√[(x+1)*2/(x+1)]=2√2
所以1/y>=3+2√2
所以0



5.5x-x=8.
完整些


5.5x-x=8.1
(5.5-1)x=8.1
4.5x=8.1
x=8.1÷4.5
x=1.8