The answers to the exercises 14.2, 6 and 7 in the first volume of mathematics published by people's education press of Grade 8 Conditions: add conditions to question 7 and find the area of the triangle formed by the line and the coordinate axis 6. Given the first-order function y = KX + B, when x = 2, the value of Y is 4, when x = - 2, the value of Y is - 2, find K and B 7. Given that the image of a function of degree passes through points (- 4,9) and (6,3), find the analytic expression of the function, and find the area of the triangle surrounded by the line and the coordinate axis

The answers to the exercises 14.2, 6 and 7 in the first volume of mathematics published by people's education press of Grade 8 Conditions: add conditions to question 7 and find the area of the triangle formed by the line and the coordinate axis 6. Given the first-order function y = KX + B, when x = 2, the value of Y is 4, when x = - 2, the value of Y is - 2, find K and B 7. Given that the image of a function of degree passes through points (- 4,9) and (6,3), find the analytic expression of the function, and find the area of the triangle surrounded by the line and the coordinate axis

⑥ When x = 2, the value of Y is 4, which is substituted into the original equation
4=2K+B
When x = - 2, the value of Y is - 2, which is substituted into the original equation
-2=-2K+B
So 4 = 2K + B
We get b = 4-2k and substitute - 2 = - 2K + B
We can get - 2 = - 2K + 4-2k
therefore
K=3/2
B=1
⑦ The analytic expression of this function is y = KX + B
X = - 4, y = 9; X = 6, y = 3
9=-4k+b
3=6k+b
k=－0.6
b=6.6
y=－0.6x＋6.6
OK, plus points, plus points. I'm serious about it