When the result of (2mx * - x * + 3x + 1) - (5x * - 4Y * + 3x) has nothing to do with the value of X, find the value of 3M & sup2; - {(2m-5) = 5m * & sup2; + 3M} *It means square

When the result of (2mx * - x * + 3x + 1) - (5x * - 4Y * + 3x) has nothing to do with the value of X, find the value of 3M & sup2; - {(2m-5) = 5m * & sup2; + 3M} *It means square

(2mx*-x*+3x+1)-(5x*-4y*+3X)=(2m-1-5)x²+4y²+1
In the title, if the result has nothing to do with the value of X, then (2m-1-5) = 0
∴m=3
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