The image f of the function y = cos (2x + π 6) - 2 is translated to f 'according to vector a. the analytic expression of F' is y = f (x). When y = f (x) is an odd function, vector a can be equal to () A. (−π6,-2)B. (−π6,2)C. (π6,-2)D. (π6,2)

The image f of the function y = cos (2x + π 6) - 2 is translated to f 'according to vector a. the analytic expression of F' is y = f (x). When y = f (x) is an odd function, vector a can be equal to () A. (−π6,-2)B. (−π6,2)C. (π6,-2)D. (π6,2)

If y = cos (2x + π 6) - 2 is shifted to the left by π 6 units, and then up by 2 units, y = cos (2x + π 2) = - sin2x  a = (− π 6,2) is obtained, so B is selected