The first-order function y = 3 / 2x + 3 and y = - 1 / 2x + Q both pass through a (m, 0) and intersect with y axis at points B and C 1 respectively. Try to find the area of △ ABC. 2. Point D is a plane The linear functions y = 3 / 2x + 3 and y = - 1 / 2x + Q pass through a (m, 0) and intersect with y axis at points B and C respectively 1. Try to find the area of △ ABC 2. Point D is a point in the plane rectangular coordinate system, and the quadrilateral with points a, B, C and D as the vertex is a parallelogram. Please write the coordinates of point d directly 3. Can we draw a straight line through the vertex of △ ABC, so that it can divide the area of △ ABC equally? If we can, we can find the functional relationship of the straight line; if not, we can explain the reason

The first-order function y = 3 / 2x + 3 and y = - 1 / 2x + Q both pass through a (m, 0) and intersect with y axis at points B and C 1 respectively. Try to find the area of △ ABC. 2. Point D is a plane The linear functions y = 3 / 2x + 3 and y = - 1 / 2x + Q pass through a (m, 0) and intersect with y axis at points B and C respectively 1. Try to find the area of △ ABC 2. Point D is a point in the plane rectangular coordinate system, and the quadrilateral with points a, B, C and D as the vertex is a parallelogram. Please write the coordinates of point d directly 3. Can we draw a straight line through the vertex of △ ABC, so that it can divide the area of △ ABC equally? If we can, we can find the functional relationship of the straight line; if not, we can explain the reason

1. First, substitute a (m, 0) into y = 3 / 2x + 3 to get m = - 2, then substitute (- 2,0) into y = - 1 / 2x + Q to get q = 1, then calculate the coordinates of B and C as (0,3) and (0,1), and then calculate the area of △ ABC as 2
2. There are three cases (- 2, - 2), (2,4), (- 2,2),
3. Energy y = x + 2