Given the vector OA = (1, K), the vector ob = (K + 1., 2), and the vector OC = (3,1), if the triangle ABC is an isosceles right triangle, then what is k

Given the vector OA = (1, K), the vector ob = (K + 1., 2), and the vector OC = (3,1), if the triangle ABC is an isosceles right triangle, then what is k

The vectors of OA, OB and OC are the coordinates of ABC. The AB vector is the subtraction of two coordinates, the horizontal minus the horizontal, the vertical minus the vertical. AB (k, 2-k) BC (2-k, - 1) AC (2,1-k) if AB is vertical to BC, then K (2-k) - (2-k) = 0, k = 1, both sides are equal. If AB is vertical to AC, then 2K + (2-k) (1-k) = 0, there is no solution. If BC is vertical to AC, then 2 (2-k) - (1-k)