In △ ABC, ab = AC, D is the point on BC, DF ⊥ AC is on fed ⊥ BC is on D, if ∠ AED = 150 °, calculate the degree of ∠ EDF?

In △ ABC, ab = AC, D is the point on BC, DF ⊥ AC is on fed ⊥ BC is on D, if ∠ AED = 150 °, calculate the degree of ∠ EDF?

Because the angle AED is equal to 150 degrees, the angle bed is equal to 30 degrees. So the angle c is equal to the angle B is equal to 60 degrees, so the angle FDC is equal to 30 degrees. So the angle EDC is equal to 90 degrees, so the angle EDF is equal to 60 degrees
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