In the triangle ABC, the extension of AB: AC = 3:5, BD = CE, de intersects the extension of BC at point F. if DF = 15, find the length of EF

In the triangle ABC, the extension of AB: AC = 3:5, BD = CE, de intersects the extension of BC at point F. if DF = 15, find the length of EF

Make DG ‖ AC
∴△BDG∽△BAC,△FEC∽△FDG
∴AB/AC=DB/DG=CE/DG=EF/DF
∵AB/AC=3/5
∴EF/DF=3/5
∵DF=15
∴EF=9
A: the length of EF is 9
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