If BC = 3, DF = 4, ∠ f = 90 °, then ∠ C =?, s triangle def =?

If BC = 3, DF = 4, ∠ f = 90 °, then ∠ C =?, s triangle def =?

Because triangle ABC is congruent with triangle def, so ∠ C = ∠ f = 90 °, BC = EF = 3, AC = DF = 4
So s triangle def = (EF × DF) △ 2 = 6