As shown in the figure, the triangle ABC is divided into two parts, AE = 3, EC = 2, BD = 3, DC = 1. What is the area ratio of the two parts

As shown in the figure, the triangle ABC is divided into two parts, AE = 3, EC = 2, BD = 3, DC = 1. What is the area ratio of the two parts

Use the triangle area formula. S = 0.5 * a * b * sinc
S small = 0.5 * 1 * 2 * sin C (C is a random angle) = sin C
SDA = 0.5 * (3 + 1) * (3 + 2) sin C = 10 sin C
The first part is s small, the second part is s big - s small = 9 sin C
The ratio was 1:9