It is known that the function f (x) = - 2 ^ x + B / [2 ^ (x + 1) + a] with the domain R is an odd function (1) Finding the value of a and B (2) If for any t ∈ R, the inequality f (T ^ 2-2t) + F (2t ^ 2-k)

It is known that the function f (x) = - 2 ^ x + B / [2 ^ (x + 1) + a] with the domain R is an odd function (1) Finding the value of a and B (2) If for any t ∈ R, the inequality f (T ^ 2-2t) + F (2t ^ 2-k)

(1) Because it is an odd function, so f (0) = 0, calculate B = 1. Then according to f (- x) = - f (x), both sides are simplified respectively, the coefficients of corresponding terms are equal, and a is solved
(2) Take T ^ 2-2t as a whole and 2T ^ 2-k as a whole into f (x), because the division is less than 0, which is actually equivalent to that the numerator multiplied by the denominator is less than 0, and the denominator is not equal to 0. If x = T ^ 2, it becomes a one variable quadratic inequality, which is less than 0. Combined with the corresponding one variable quadratic function and image, the discriminant can be done (the process is very troublesome -- |)