Given the set a = {x | X & # 178; + BX + C = 0} = {1,2}, try to find the value of real numbers B and C

Given the set a = {x | X & # 178; + BX + C = 0} = {1,2}, try to find the value of real numbers B and C

{x|x²+bx+c=0}={1,2}
That is to say, the equation x & # 178; + BX + C = 0 is followed by 1 and 2
So 1 + 2 = - B
1*2=c
therefore
b=-3
c=2