If sin ^ 2x is greater than cos ^ 2x, then the value range of X is Make the unit circle and the straight line y = x.y = - x on the rectangular axis, and then do it according to the definition of triangle?

If sin ^ 2x is greater than cos ^ 2x, then the value range of X is Make the unit circle and the straight line y = x.y = - x on the rectangular axis, and then do it according to the definition of triangle?

A, a ': SiNx = cosx = √ 2 / 2 (SiNx) ^ 2 = (cosx) ^ 2Y = x and Y axis (acute angle area), SiNx > cosx circle O and y = - x intersect B (- 1,1), B' (1, - 1) B, B 'SiNx = - cosx = - 2 / 2 (SiNx) ^ 2 = (cosx) ^ 2Y = - X and Y axis (acute angle area), Bo