Limx - > ∞ arctan (√ x2 + 2x-x) how to use the continuity of function to find the limit and kneel down to find the answer It's the square of the root x plus 2x, and then minus X.

Limx - > ∞ arctan (√ x2 + 2x-x) how to use the continuity of function to find the limit and kneel down to find the answer It's the square of the root x plus 2x, and then minus X.

Limx->∞arctan(√x2+2x-x)
=lim arctan{2x/[√x2+2x+x }
=lim arctan{2/{√(1+2/x)+1}}
=arctan1
=π/4