The slope and inclination angle of a straight line If two points a (x1, Y1), B (X2, Y2) are on the straight line with direction vector a = (1, K) and ab = t, then | y1-y2 | =? The answer is t|k | / radical (k ^ 2 + 1)

The slope and inclination angle of a straight line If two points a (x1, Y1), B (X2, Y2) are on the straight line with direction vector a = (1, K) and ab = t, then | y1-y2 | =? The answer is t|k | / radical (k ^ 2 + 1)

Let a (x1, Y1) B (X2, Y2) C (X2, Y1) form a right triangle
Let AC length be x and BC length be y, then x ^ 2 + y ^ 2 = T ^ 2; - (1)
And because the direction vector is (1, K), so y / x = k; - (2)
(1) (2) simultaneous y = | y1-y2 | = your results
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