In the triangular pyramid p-abc, it is known that PA = Pb = PC = 2, ∠ BPA = ∠ BPC = ∠ CPA = 30 ° and the shortest distance of a rope from point a to point a is______ .

In the triangular pyramid p-abc, it is known that PA = Pb = PC = 2, ∠ BPA = ∠ BPC = ∠ CPA = 30 ° and the shortest distance of a rope from point a to point a is______ .

Let AEF cross the sides of Pb and PC at two points E and F, and expand the triangular pyramid from PA, then ∠ apa1 = 90 ° Aa1 is the shortest distance of the rope from the side of point a to point E on Pb, then to point F on PC, and then back to point a, ∵ PA = 2, ∵ Aa1 = 4 + 4 = 22 can be obtained from Pythagorean theorem