The derivative of F (x) + 2F (1) = 1 + LNX / 2 to find f (x) F (x) + 2F '(1) = 1 + (LNX) / 22F' (1) is the derivative of twice f (1)

The derivative of F (x) + 2F (1) = 1 + LNX / 2 to find f (x) F (x) + 2F '(1) = 1 + (LNX) / 22F' (1) is the derivative of twice f (1)

It's not very clear. Derivative tube or something?
For both sides of the formula F (x) + 2F '(1) = 1 + (LNX) / 2, the derivation of X is obtained
F '(x) = 1 / (2x), so f' (1) = 1 / 2,
So f (x) = - 2F '(1) + 1 + (LNX) / 2
=(lnx)/2