Finding the n-order derivative y ^ (n) of y = x / radical (2-x) How to calculate and the answer is not the same!

Finding the n-order derivative y ^ (n) of y = x / radical (2-x) How to calculate and the answer is not the same!

First decompose y = [2 - (2-x)] / √ (2-x) = 2 / √ (2-x) -√ (2-x) = 2 * (2-x) ^ (- 1 / 2) - (2-x) ^ (1 / 2), so y (n) = 2 (- 1 / 2) (- 3 / 2)... (- 2n-1) / 2) * (2-x) ^ (- (2n + 1) / 2) * (- 1) ^ n - (1 / 2) (- 1 / 2)... (- 2n-3) / 2) * (2-x) ^ (- (2n-1)) * (- 1) ^ n = 2 * (- 1)

Elden Ring Premiere

RELATED INFORMATIONS