When x > 0, the function FX is meaningful and satisfies F 2 = 1, f (XY) = FX + FY, FX is an increasing function (1) Verification: F (1) = 0 (2) If f (3) + F (4-8x) > 2, find the value range of X

When x > 0, the function FX is meaningful and satisfies F 2 = 1, f (XY) = FX + FY, FX is an increasing function (1) Verification: F (1) = 0 (2) If f (3) + F (4-8x) > 2, find the value range of X

（1 ）
f(xy)=fx+fy
Let x = 2, y = 1. Then f (1 * 2) = f (2) + F (1), so f (1) = 0
(2) Use that equation
f(3)+f(4-8x)=f(3+4-8x)>f(2*2)=f(2)+f(2)=2
Because FX is an increasing function, 3 + 4-8x > 2 * 2 is X

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