Three sets a = {X / x ^ 2-3x + 2 = 0}, B = {X / x ^ 2-ax + A-1 = 0}, C = {X / x ^ 2-bx + 2 = 0}, if a is the proper subset of B, AUC = a is the real number a, does B exist? If yes, find out a, B. if not, explain the reason B is the true subset of A, I don't quite understand

Three sets a = {X / x ^ 2-3x + 2 = 0}, B = {X / x ^ 2-ax + A-1 = 0}, C = {X / x ^ 2-bx + 2 = 0}, if a is the proper subset of B, AUC = a is the real number a, does B exist? If yes, find out a, B. if not, explain the reason B is the true subset of A, I don't quite understand

It's estimated that you will be promoted to senior three this year. The poor child is still up. Come on~
I had been studying mathematics for two years, but I forgot all about it
Help you to see the solution to change the answer
X ^ 2-3x + 2 = 0, x = 1, x = 2, so a = {1,2}
And B = {a, 1}
And because a is the proper subset of B, a = 2
Because AUC = a, so
1 when C = {1,2}, B = 3
2 when C = {1} there is no solution
3 when C = {2}, there is no solution
Let's consider Delta, which is one solution and two solutions of the equation
4 when C is an empty set
It's not easy to write down the back with the keyboard
I don't know if it's right