Given the set a = {- 4,2a-1, the square of a}, B = {a-5,1-a, 9}, whether there is a real number a such that there are four elements in the set a and B, and calculate the value of A

Given the set a = {- 4,2a-1, the square of a}, B = {a-5,1-a, 9}, whether there is a real number a such that there are four elements in the set a and B, and calculate the value of A

1) If - 4 = a-5 = = > A = 1A = {- 4,1,1} contradiction! 2) if - 4 = 1-A = = > A = 5A = {- 4,9,25}; b = {0, - 4,9} = = > a ∩ B = {- 4,9,25,0} satisfies the condition! 3) if 2a-1 = a-5 = = > A = - 4A = {- 4, - 9,4}; b = {- 9,5} a ∩ B = {- 4,9,4, - 9,5}, it is not right; 4) 2a-1 = 1-aa = 2 / 3; a = {

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