Mathematical application problems. Equations to be listed. Fractional application The speed ratio of a to B is 2:3. The distance from a and B to C is 10.5 km and 12 km respectively. If a starts one hour earlier than B, it can arrive 30 minutes earlier than B. how much speed can a and B walk?

Mathematical application problems. Equations to be listed. Fractional application The speed ratio of a to B is 2:3. The distance from a and B to C is 10.5 km and 12 km respectively. If a starts one hour earlier than B, it can arrive 30 minutes earlier than B. how much speed can a and B walk?

Let V A = 2xkm / h, v b = 3xkm / h
According to the meaning of the title: 10.5-2x-1 / 2 = 12.3x
The solution is: x = 2.5
So 2x = 5
3x=7.5
A: the speed of step a is 5 km / h, and that of step B is 7.5 km / h