Given x + y = 36 and 4x + 2Y = 100, how much is x and y

Given x + y = 36 and 4x + 2Y = 100, how much is x and y

x+y=36
x=36-y.①
4x+2y=100.②
We can get the following results
4(36-y)+2y=100
144-4y+2y=100
144-100=4y-2y
44=2y
y=22.③
Substituting (3) into (1) yields:
x=36-22
=14
therefore
x=14
y=22
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