On the smooth horizontal plane, two blocks a and B with the same mass m and thickness d are arranged side by side. A bullet C with mass m shoots at the two blocks at the horizontal velocity v0 On the smooth horizontal plane, there are two identical blocks a and B with mass m and thickness d side by side. A bullet C with mass m shoots at two blocks with horizontal velocity v0. The velocity of the bullet after passing through the first block a is V0 / 2. The bullet is finally embedded in the second block B. what is the final velocity of the two blocks

On the smooth horizontal plane, two blocks a and B with the same mass m and thickness d are arranged side by side. A bullet C with mass m shoots at the two blocks at the horizontal velocity v0 On the smooth horizontal plane, there are two identical blocks a and B with mass m and thickness d side by side. A bullet C with mass m shoots at two blocks with horizontal velocity v0. The velocity of the bullet after passing through the first block a is V0 / 2. The bullet is finally embedded in the second block B. what is the final velocity of the two blocks

Initial momentum = MV0
When the bullet just passes through the first block, the two blocks have the same speed: MV0 = MV0 / 2 + 2mv1, V1 = MV0 / (4m), which is the final speed of the first block
When the bullet is embedded in the second block, the velocity is the same as that of the block, MV0 / 2 + MV1 = (M + m) V2, V2 = 3mv0 / (4m + 4m), which is the final velocity of the second block