As shown in the figure, there is an object with mass m = 1kg on a fixed inclined plane with an inclination angle of 37 ° and enough length, and the dynamic friction coefficient between the object and the inclined plane is μ = 0.5. The object starts from the bottom of the inclined plane and slides upward along the inclined plane, and its initial velocity is V0 = 10m / s? (2) What is the kinetic energy of an object returning to the bottom of the slope? （sin37°=0.6，cos37°=0.8，g=10m/s2）

As shown in the figure, there is an object with mass m = 1kg on a fixed inclined plane with an inclination angle of 37 ° and enough length, and the dynamic friction coefficient between the object and the inclined plane is μ = 0.5. The object starts from the bottom of the inclined plane and slides upward along the inclined plane, and its initial velocity is V0 = 10m / s? (2) What is the kinetic energy of an object returning to the bottom of the slope? （sin37°=0.6，cos37°=0.8，g=10m/s2）

(1) When the object is sliding upward, the acceleration of the object is a = - (GSIN θ + μ GCOS θ). Substituting into the data, a = - 10m / S2 is obtained. From the formula - V02 = 2As, s = V02 − 2a is obtained. Substituting into the data, s = 5 & nbsp; m (2) the whole process is obtained by using the kinetic energy theorem: EK = 12mv02 − 2 μ mgscos θ