An object with a mass of 2kg is still on a horizontal plane and starts to move under the action of a horizontal constant force of 10N. It moves 8m in 2S 1. Work done by horizontal constant force W 2. Average power of work done by horizontal constant force P The instantaneous power p'of the work done by the horizontal constant force at the end of 3.2 seconds How can FV get 400. Wrong,

An object with a mass of 2kg is still on a horizontal plane and starts to move under the action of a horizontal constant force of 10N. It moves 8m in 2S 1. Work done by horizontal constant force W 2. Average power of work done by horizontal constant force P The instantaneous power p'of the work done by the horizontal constant force at the end of 3.2 seconds How can FV get 400. Wrong,

We need to add conditions to smooth the horizontal plane
W=Fs=10N×8m=80J
P=W/t=80J/2s=40W
Acceleration a = f / M = 10N / 2kg = 5m / S ^ 2
2 s final velocity v = at = =10m/s
Instantaneous power at the end of 2S p '= FV = 10N × 10N / S = 100W