If the acceleration of the object is 2m / S ^ 2, the displacement in the first second is 2m, then the displacement in the third second

If the acceleration of the object is 2m / S ^ 2, the displacement in the first second is 2m, then the displacement in the third second

The initial velocity can be calculated as 1m / s according to x = VOT + & frac12; at & sup2
Then calculate the displacements in 3 seconds and 2 seconds, which are 12 meters and 6 meters respectively, and then subtract the two to get the answer. The answer is 6 meters