When an object moves in a straight line with uniform acceleration, the displacement is 10 m in the third second and 14 m in the fifth second, Here is my process 1/2a+V0=10 1 1/2a+V0'=14 2 Here, V0 refers to the velocity at the end of the second second second, and V0 'refers to the velocity at the end of the fourth second 1-2 to get V0 '- V0 = 4 So a = 2m / S ^ 2 Then 1 / 2 × 2 + V0 = 10 So the initial velocity is 8m / s But the initial speed in the answer is 5m / s, which I don't understand. I hope you can analyze the problems in my process,

When an object moves in a straight line with uniform acceleration, the displacement is 10 m in the third second and 14 m in the fifth second, Here is my process 1/2a+V0=10 1 1/2a+V0'=14 2 Here, V0 refers to the velocity at the end of the second second second, and V0 'refers to the velocity at the end of the fourth second 1-2 to get V0 '- V0 = 4 So a = 2m / S ^ 2 Then 1 / 2 × 2 + V0 = 10 So the initial velocity is 8m / s But the initial speed in the answer is 5m / s, which I don't understand. I hope you can analyze the problems in my process,

Children's shoes, are you flustered~
You solved V0, which is the velocity at the end of the second second. It seems that you have miscalculated V0 = 9m / s
Then calculate the initial velocity v = v0-2a = 9-4 = 5m / s,
Right~