The cyclist rides on a 30 m long slope with an initial speed of 5 m / S2 per second, and the acceleration is 0.4 m / S2 Q: 1. How fast does the bicycle reach the top of the slope? 2. What is the displacement in the second second?

The cyclist rides on a 30 m long slope with an initial speed of 5 m / S2 per second, and the acceleration is 0.4 m / S2 Q: 1. How fast does the bicycle reach the top of the slope? 2. What is the displacement in the second second?

(1) Suppose you use time t to ride up the slope and reach the top of the slope
Vo=5m/s,a=-0.4m/s^2, S=30m
S=Vot+(1/2)at^2
30=5t-0.5*0.4t^2
T1 = 10s, T2 = 15s
Calculated time: T = 10s
（2）
According to v = V0 at = 5-0.4 х 10 = 1m / S
The displacement in the second second is obtained by subtracting the displacement in the first second from the displacement in the second second
X=x2-x1=9.2-4.8=4.4m