About springs, rubber ropes and ropes! Isn't the tension constant at the moment when the spring and the rubber rope break? For example, when the rope and the spring are used to bolt a heavy object and a wooden pole respectively, the tension of the spring on it doesn't change at the moment when it is cut? Here is a question that is a little incomprehensible: "in children's bungee jumping," the elastic rubber rope tied to the left and right sides of the waist is excellent, The tension of the two rubber ropes is just Mg (that is, the angle between the two of the three ropes is 120 degrees). The moment when the rubber rope on Xiaoming's left side breaks () why is the answer: acceleration a = g, the direction is opposite to the original tension direction of the broken rubber rope? The speed keeps the same with the situation. But the analysis of acceleration means that the rubber rope on the left side breaks, and because of the instantaneous invariance of the rubber rope, So the tension of the right rubber rope is constant, so the acceleration is g, which is opposite to the original tension direction of the broken rubber rope. My idea is that the left rubber rope should also have instantaneous invariance? Please answer my question comprehensively

About springs, rubber ropes and ropes! Isn't the tension constant at the moment when the spring and the rubber rope break? For example, when the rope and the spring are used to bolt a heavy object and a wooden pole respectively, the tension of the spring on it doesn't change at the moment when it is cut? Here is a question that is a little incomprehensible: "in children's bungee jumping," the elastic rubber rope tied to the left and right sides of the waist is excellent, The tension of the two rubber ropes is just Mg (that is, the angle between the two of the three ropes is 120 degrees). The moment when the rubber rope on Xiaoming's left side breaks () why is the answer: acceleration a = g, the direction is opposite to the original tension direction of the broken rubber rope? The speed keeps the same with the situation. But the analysis of acceleration means that the rubber rope on the left side breaks, and because of the instantaneous invariance of the rubber rope, So the tension of the right rubber rope is constant, so the acceleration is g, which is opposite to the original tension direction of the broken rubber rope. My idea is that the left rubber rope should also have instantaneous invariance? Please answer my question comprehensively

In fact, what you said is quite right. You killed the person who wrote the question. The person who wrote the question didn't have as much as you thought
What he meant was that the one on the left disappeared out of thin air
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Add two sentences:
Of course, there is another serious problem in this question, that is, the question does not say whether the rubber rope is light. If it is light, then it can not be broken, it can only disappear (this is the reason why I said the person who asked the question means to disappear); if it is not light, then the rubber rope itself will not be fully straightened under tension, so the 120 degree is a problem
In a word, this question can't stand scrutiny. Just don't let it go