[physics of grade one in senior high school] acceleration and force problems of trolley motion The question has a picture There is a sentence in the answer: the small plate and the weight pull the car, and the force to make the car do uniform acceleration linear motion is equal to the gravity of the small plate and the weight Let t be the one pulling the trolley and Mg be the gravity. Then, is it not mg-t = ma that we are doing the uniform acceleration motion now? How can we make the force of the trolley doing the uniform acceleration linear motion equal to the gravity of the small plate and the weight?

[physics of grade one in senior high school] acceleration and force problems of trolley motion The question has a picture There is a sentence in the answer: the small plate and the weight pull the car, and the force to make the car do uniform acceleration linear motion is equal to the gravity of the small plate and the weight Let t be the one pulling the trolley and Mg be the gravity. Then, is it not mg-t = ma that we are doing the uniform acceleration motion now? How can we make the force of the trolley doing the uniform acceleration linear motion equal to the gravity of the small plate and the weight?

This is a problem in an inquiry experiment of physics in grade one of senior high school "exploring the relationship between acceleration and force and mass of the car". In fact, the force that makes the car do uniform acceleration and linear motion is not equal to the gravity of the small plate and the weight. However, because the gravity of the car is far greater than that of the small plate and the weight, it can be considered as such
Suppose the mass of the car is m, the mass of the plate and the weight is m, and the force of pulling the car is t
Car: T = ma
Plate and weight: mg-t = ma
In this case, only when m > m, t = mg
I am a physics teacher, ha ha ha. I know this when I talk about it, but I will forget it later