When an object is accelerating uniformly, the initial velocity is 0.5m/s, and the displacement in the second second second is 4m more than that in the first second It can be calculated with △ x, but why can't it be calculated with x = v0t + 0.5at ^ 2

When an object is accelerating uniformly, the initial velocity is 0.5m/s, and the displacement in the second second second is 4m more than that in the first second It can be calculated with △ x, but why can't it be calculated with x = v0t + 0.5at ^ 2

The displacement of the first 2S can be expressed as x = v0t2 + at2 ^ 2 / 2 = 0.5 × 2 + 4A / 2 = 1 + 2a, the displacement of the first 1s can be expressed as X1 = v0t1 + AT1 ^ 2 / 2 = 0.5 × 1 + A / 2 = 0.5 + 0.5A, then the displacement of the second 2S is the difference between the two formulas: x2 = x-x1 = 1 + 2A - (0.5 + 0.5A) = 0.5 + 1.5A