If the displacement is 6 meters in the first second and 2 meters in the last second before stopping, then: (1) during the whole deceleration If the displacement in the first second is 6 meters and that in the last second before stopping is 2 meters, then: (1) what is the displacement of the car in the whole deceleration process? (2) how much time does the whole deceleration process share?

If the displacement is 6 meters in the first second and 2 meters in the last second before stopping, then: (1) during the whole deceleration If the displacement in the first second is 6 meters and that in the last second before stopping is 2 meters, then: (1) what is the displacement of the car in the whole deceleration process? (2) how much time does the whole deceleration process share?

From the displacement of the last second before the movement stops to 2m,
Then: S = at ^ 2 / 2, we can get: a = 4 m / S ^ 2
The displacement in the first second is 6 meters
Then: v0t at ^ 2 / 2 = 6 can get: V0 = 8 m / s
(1) What is the displacement of the car in the whole deceleration process?
t=v/a=8/4=2 s
s=at^2/2=4*4=16 m
(2) How much time does the whole deceleration process take?
T = 2 s see the first question