After entering the station, the car starts to brake and decelerate in a straight line. In the first second, the displacement is 9 m and 7 m respectively After entering the station, the car starts to brake and make a uniform deceleration linear motion. The displacement in the first second is 9m and 7m in turn. Then what is the displacement in the sixth second after braking? Why can we use the displacement difference 2m to get 9,7,5,3,1,0m? Why is it 0m in the end

After entering the station, the car starts to brake and decelerate in a straight line. In the first second, the displacement is 9 m and 7 m respectively After entering the station, the car starts to brake and make a uniform deceleration linear motion. The displacement in the first second is 9m and 7m in turn. Then what is the displacement in the sixth second after braking? Why can we use the displacement difference 2m to get 9,7,5,3,1,0m? Why is it 0m in the end

Because in a short time, uniform deceleration can be regarded as uniform motion, and the displacement ratio of time is velocity, so the velocity in the first second is 9 / 1 = 1m / s. similarly, the velocity in the second second second is 7m / s, so the acceleration is - 2m / S2. From the surface, you can draw the conclusion you want, because the car stops before the sixth second, so the final value is 0