1. If f (x) = x ^ 2 + ax + 3, if x ∈ [- 2,2], f (x) ≥ a, find the range of A 2. For any x ∈ R, we know that f (x) + F (y) = f (x + y), and when x > 0, f (x) + F (y) = f (x + y), f(x)

1. If f (x) = x ^ 2 + ax + 3, if x ∈ [- 2,2], f (x) ≥ a, find the range of A 2. For any x ∈ R, we know that f (x) + F (y) = f (x + y), and when x > 0, f (x) + F (y) = f (x + y), f(x)

When - A / 2 < - 2, i.e. a > 4, f (x) is an increasing function on (- A / 2, + ∝). When x = - 2, f (x) is the minimum = 7-2a ≥ a, a ≤ 7 / 3. There is no solution. When - a / 2 > 2, i.e. a < - 4, f (x) is a decreasing function on (- A / 2, + ∝). When x = 2, f (x) is the minimum = 7 + 2A ≥ a, a ≥ - 7 ∝ - 7