On a straight road, two cars go in the same direction. At the beginning, car a is 4km in front of car B. the speed of car a is 45km / h, and that of car B is 60km / h. how many meters is the distance between the two cars one minute before car B catches up with car a? First order equation with one variable is solved,

On a straight road, two cars go in the same direction. At the beginning, car a is 4km in front of car B. the speed of car a is 45km / h, and that of car B is 60km / h. how many meters is the distance between the two cars one minute before car B catches up with car a? First order equation with one variable is solved,

Car B is 60-45 faster than car a = 15km / h = 250m / min
One minute before catching up, the two cars were 250 meters apart
The first condition doesn't work
If you have to use equations
Then set a distance of X meters
x=(60-45)×1000÷60×1
The solution is x = 250