In order to reduce the number of matches, 20 teams are divided into two groups (10 teams in each group) for competition, and the probability of (1) the strongest two teams being divided into different groups and (2) the probability of being divided into the same group is calculated.

In order to reduce the number of matches, 20 teams are divided into two groups (10 teams in each group) for competition, and the probability of (1) the strongest two teams being divided into different groups and (2) the probability of being divided into the same group is calculated.

If you have the basis of permutation and combination, you should be able to understand my solution
As the formula can't be edited here, see the picture for details: